All right for this question, we're solving for the value of KC, and we don't know, the equilibrium concentration. So we have to set up an ice table in order to solve for this so set up your ice table with your reactants and products, which in this case, there's only two species present in the reaction. We've got n 2, O, 4 and 2 and O 2 set up your ice table, initial change equilibrium and then sub in the values that you're given in the question. So the information that I have is I know, there are two moles of. My product introduced in a 2-liter ball. So remember whatever eats up into your ice table has to be in moles per liter, the champion moles or champion grams of caffeine. Liters it's got to be moles per liter.

So two moles of n2o4 divided by two liters gives us one mole per liter. So we can sub that in for our initial value at the end. We have one point. Six moles remaining remember that we don't want to sub in one point, six here because it's not in moles per liter. So just like the first just like the. First value that we were given of two moles. We also have to convert the one point, six moles into moles per liter.

So one point six moles of n2o4 divided by a two liter container gives us 0.8 moles per liter at the end. So from this information I can determine that the change is a decrease, so it's a minus. And it was a change of 0.2 moles per liter. Okay for this column for your change, the row that for that has to change values. This is where we can use the mole ratio to figure out the change of any.

Other reactants or products. So my mole ratio here would be 2 over 1. So I would time this by 2 over 1 to give me the change for my no.2, and it's going to be an increase. So we write it as positive. 0.4, I can fill in the rest. Initially it doesn't say anything about having product present.

So I can assume that it's zero. And at the end I'm going to have point, four moles per liter. So if we set up our equilibrium expression to calculate, KC, remember KC is always products over reactants.

So we sub this in as. Kc equals zero point, four squared divided by 0.8, which gives us a value gives us a value of zero point. Two.

So this means that the reaction is less than 50%. And our products are going to be favored because my K value is less than one else. Pearlie.

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